#include<iostream>
#include<math.h>
using namespace std;
int main()
{
int a,b,c;
float d,x1,x2,x;
cout<<"a= ";cin>>a;
cout<<"b= ";cin>>b;
cout<<"c= ";cin>>c;
d=b*b-4*a*c;
Switch(d)
{
case d==0:
x=-b\2*a;
cout<<"x= "<<x;break;
case d<0:
cout<<"Solutia e nr complex fraiere";break;
default:x1=(-b+(sqrt(d)))/2*a; x2=(-b-(sqrt(d)))/2*a;
cout<<"x1= "<<x1;
cout<<"x2= "<<x2;
}
}
vreau sa rezolv o ecuatie de gradu 3 folosind case. :-? Ce am gresit?
Ce am gresit? #3 c++
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- G3ner1c
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Last edited by G3ner1c on 08 Nov 2013, 23:17, edited 2 times in total.
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O posibila varianta ar fi sa pui totul intr-un loop pana introduci zero.
Code: Select all
do {
switch() {}
}
}while(n!=0)
- G3ner1c
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return main(); ms frumos, e o idee buna si cu loop-ul :DIsTI37 wrote:return main(); sau main(); la sfarsit daca imi amintesc bine...
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Astea ce fel de date definesc?
long n;
char n;
double n;
long n;
char n;
double n;
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double - ii o variabila, stiu de la java.
char - un character, un cuvant parca tot de la java stiu asta. cred ca char ii tot un fel de variabila
long - nu stiu..
char - un character, un cuvant parca tot de la java stiu asta. cred ca char ii tot un fel de variabila
long - nu stiu..
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max short = 2^15 - 1 = 32767
max unsigned short = 2^16 - 1 = 65535
max int = 2^31 - 1 = 2147483647
max unsigned int = 2^32 - 1 = 4294967295
max float = 2^(2^7) = 3.4 x 10^38
max double = 2^(2^10) = 1.798 x 10^308
si char e legat de caractere de tip litere.
max unsigned short = 2^16 - 1 = 65535
max int = 2^31 - 1 = 2147483647
max unsigned int = 2^32 - 1 = 4294967295
max float = 2^(2^7) = 3.4 x 10^38
max double = 2^(2^10) = 1.798 x 10^308
si char e legat de caractere de tip litere.
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http://www.cplusplus.com/doc/tutorial/variables/ - le gasesti pe toate aici.G3ner1c wrote:Astea ce fel de date definesc?
long n;
char n;
double n;
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ok, ms am inteles, dar rezolvarea la problema aia care este? b-(
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