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Maadalin
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30 Jun 2015, 17:23

Cum se rezolva?Aveti poza mai jos.
| Afiseaza codul
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Last edited by Maadalin on 30 Jun 2015, 17:24, edited 1 time in total.
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micleanu
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30 Jun 2015, 17:24

nu merge imaginea
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fan_haulin
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30 Jun 2015, 18:09

Prima oara Conditii de existenta:
2x-1 > 0 => 2x>1 =>x > 1/2 => x apartine (1/2 ;infinit)
(2x-1)/3 = 5^0 <=>(2x-1)/3 = 1 <=> 2x-1 = 3 <=> 2x = 4 <=> x = 2 apartine (1/2 ; infinit)
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