Am o rugaminte la cei care se pricep la matematica, daca imi pot calcula ecuatia de mai jos, dar explicata pentru a imi da seama cum se face:
1023 = 2(la puterea N) - 1
Sa se afle N.
Ecuatie matematica
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- Laur eXtream
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1023 = 2(la puterea N) - 1
2 la puterea N = 1023 + 1 = 1024
2 la puterea 10 = 1024 => 10 este N-ul.
2 la puterea N = 1023 + 1 = 1024
2 la puterea 10 = 1024 => 10 este N-ul.
- Laur eXtream
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Pai da dar cum ti-a dat 10 ?
- ADM1N
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Eu am descompus numarul 1024 si vedeai la ce putere este.Laur eXtream wrote:Pai da dar cum ti-a dat 10 ?
Iti dai seama usor.
- Laur eXtream
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Scrie formula te rog.ADM1N wrote:Eu am descompus numarul 1024 si vedeai la ce putere este.Laur eXtream wrote:Pai da dar cum ti-a dat 10 ?
Iti dai seama usor.
- zigweed
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Nu este nicio formula in pana mea, descompui numarul 1024 doar:
1024 | 2
512 | 2
256 | 2
128 | 2
64 | 2
32 | 2
16 | 2
8 | 2
4 | 2
2 | 2
1
Si acum numeri cati de 2 ai, si aia e puterea, in cazul de fata 10, deci 2^10 = 1024.
1024 | 2
512 | 2
256 | 2
128 | 2
64 | 2
32 | 2
16 | 2
8 | 2
4 | 2
2 | 2
1
Si acum numeri cati de 2 ai, si aia e puterea, in cazul de fata 10, deci 2^10 = 1024.
- Laur eXtream
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Da, asta nu mai stiam, multumesc !zigweed wrote:Nu este nicio formula in pana mea, descompui numarul 1024 doar:
1024 | 2
512 | 2
256 | 2
128 | 2
64 | 2
32 | 2
16 | 2
8 | 2
4 | 2
2 | 2
1
Si acum numeri cati de 2 ai, si aia e puterea, in cazul de fata 10, deci 2^10 = 1024.
- fan_haulin
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de fapt:
1023 = 2^n - 1
1023 + 1 = 2^n
1024 = 2^n
2^10 = 2^n => (injectivitatea exponentialei) -> n = 10
1023 = 2^n - 1
1023 + 1 = 2^n
1024 = 2^n
2^10 = 2^n => (injectivitatea exponentialei) -> n = 10
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probleme de astea incep sa fac eu, defapt am inceput sa intram in materia de clasa a opta chiar daca suntem a 7-a.
- hockz94
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a 7-a? REALLY ?!?! :eye: :eye:LondoN eXtream wrote:probleme de astea incep sa fac eu, defapt am inceput sa intram in materia de clasa a opta chiar daca suntem a 7-a.